 14 Feb.
 14 Feb. 
 
  
 
  m) 
 wound in a circle of radius 9.5 m.  The conductor has a 
 rectangular cross section (2.5 cm
m) 
 wound in a circle of radius 9.5 m.  The conductor has a 
 rectangular cross section (2.5 cm  42 cm).  
 There are 15 turns in the top half of the magnet and 15 in the 
 bottom half, for a total length of 30 circumferences (the top and 
 bottom coils are connected in series).  
 If we apply 100 V to the coils, what current flows through it?  
 How much power does this require to run?
42 cm).  
 There are 15 turns in the top half of the magnet and 15 in the 
 bottom half, for a total length of 30 circumferences (the top and 
 bottom coils are connected in series).  
 If we apply 100 V to the coils, what current flows through it?  
 How much power does this require to run?  
 
 kV, 
C = 6.5
 kV, 
C = 6.5  F and 
R1 = R2 = R3 = R = 0.73 M
F and 
R1 = R2 = R3 = R = 0.73 M .
 With C completely uncharged, 
 switch S is suddenly closed (at t=0).
.
 With C completely uncharged, 
 switch S is suddenly closed (at t=0).  
  .
.
  .
.
  ?
? 
  '' in this case.
'' in this case.  
 
 Edition)
 Edition) 
Ch. 26: problems 31, 91, 110, 137 and 153
 
You have seen how to use  GAUSS' LAW to derive the 
 radial (r) dependence of the electric field E(r>R) 
 outside charge distributions of 
 spherical, cylindrical or planar symmetry, 
 where R is the distance the charge distribution extends 
 from the centre of symmetry - the radius of a 
 charged sphere or cylinder, or half the thickness 
 of an infinite slab of charge, respectively.  
 Use similar arguments to show that, for each of these cases 
 (a sphere,  cylinder or a slab of uniform charge density), 
 the electric field E(r<R) inside the charge distribution 
 is given in terms of the field E(R) at the boundary 
 of the charge distribution by 
 
